fixed mistakes
This commit is contained in:
@@ -1,17 +1,22 @@
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--Задание 1. Оформление заказа
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BEGIN;
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INSERT INTO orders (user_id, order_date, status)
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VALUES (10, '2025-01-15', 'paid');
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INSERT INTO orders
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(user_id, order_date, status)
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VALUES
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(10, '2025-01-15', 'paid');
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INSERT INTO order_items (product_id, quantity, price_at_purchase)
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VALUES(6, 1, 4800), (7, 1, 5200);
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INSERT INTO order_items
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(order_id, product_id, quantity, price_at_purchase)
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VALUES
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(LASTVAL(), 6, 1, 4800),
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(LASTVAL(), 7, 1, 5200);
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UPDATE products
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SET in_stock = TRUE
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WHERE id IN (6, 7);
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UPDATE products
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SET in_stock = FALSE
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WHERE id IN (6, 7);
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COMMIT;
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COMMIT;
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/*Что в данных пойдёт не так, если часть шагов выполнится, а часть нет?
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В таком случае транзакция не будет закрыта. Я начал бегин, но произошла ошибка внутри транзакции и поэтому dbeaver дальше ничего выполнять не будет пока я не сделаю откат, либо не скажу завершить.
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@@ -20,7 +20,7 @@
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--просто прочитает данные. Боб лишь заблокирован для изменений.
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--что будет с UPDATE users SET country = 'FR' WHERE id = 2;.
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--В таком случае БД увидит конфликт и одну из транзакций откатит с ошибкой , а вторую пропустит дальше.
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--В таком случае БД зависнет (blocked) и будет ждать пока первая транзакция не исполнится.
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--Задание 4. Дедлок на двух пользователях
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--Объясни своими словами, почему возникает дедлок и что сделает база с одной из транзакций.
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@@ -50,8 +50,8 @@ WHERE EXTRACT(YEAR FROM created_at) = 2026
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SELECT id, name, age
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FROM users
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WHERE
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created_at >= '2024-01-01' AND created_at < '2025-01-01'
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AND country = 'RU'
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created_at >= '2026-01-01' AND created_at < '2027-01-01'
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AND country = 'россия'
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AND age > 25;
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Исправлено: выдача колонок "все" заменено на "определенные", логика в where с числами переработана, соответствие определенному году переработано и убрал функцию LOWER.
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@@ -1,12 +1,18 @@
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--Задача 1 — Читаем план
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EXPLAIN
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SELECT name, email
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FROM users
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WHERE id = 1;
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Какой тип сканирования использует база?
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--SeqScan - сканирование всей таблицы
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Что означает строка `Index Cond: (id = 1)`?
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-- У меня нет такой строки, есть "Filter: (id = 1)". Видимо это фильтрация по определенному значению, но в моем случае это должен быть индекс по столбцу id, но у меня индексы не проставлены, хорошо, что я хотя бы сейчас это уже понимаю.
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-- Строка означает фильтрацию столбца по индексу, который есть в столбце id.
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Почему база использует индекс, а не читает всю таблицу?
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--Потому что так быстрее и менее затратно.
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--В моем случае БД читает всю таблицу, но обычно если индексы расставлены верно и таблица больших размеров, то БД лучше использовать индексы для повышенной производительности.
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----------
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--Задача 2 — Seq Scan vs Index Scan
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@@ -6,7 +6,8 @@ SELECT
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COUNT(DISTINCT pu.id) AS users_in_cohort,
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COUNT(DISTINCT pe.user_id) AS enrolled_users,
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COUNT(DISTINCT plv.user_id) AS active_users,
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ROUND(COUNT(DISTINCT plv.user_id) * 100.0 / COUNT(DISTINCT pu.id), 2) || '%' AS retention_rate,
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--ROUND(COUNT(DISTINCT plv.user_id) * 100.0 / COUNT(DISTINCT pu.id), 2) || '%' AS retention_rate,
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ROUND(COUNT(pe.id) * 100.0 / COUNT(DISTINCT pu.id), 2) || '%' AS retention_rate,
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ROUND(AVG((SELECT COUNT(pe.id)
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FROM pet_enrollments pe)) / COUNT(DISTINCT pu.id), 2) AS avg_courses_per_user,
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(SELECT
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@@ -5,8 +5,8 @@ SELECT
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pl.title AS lesson_title,
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pc.id AS course_id,
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pc.title AS course_title,
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total_views_lesson.total_views AS total_views,
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table_unique_viewers.unique_v AS unique_viewers,
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COALESCE(total_views_lesson.total_views, 0) AS total_views,
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COALESCE(table_unique_viewers.unique_v, 0) AS unique_viewers,
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ROUND(AVG(views_one_user_per_one_lesson.views_per_viewer), 2) AS avg_views_per_viewer, --также это можно было посчитать total_views/unique_viewers
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DENSE_RANK() OVER (
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PARTITION BY pc.id
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@@ -1,152 +1,156 @@
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CREATE MATERIALIZED VIEW conversion_funnel AS
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CREATE MATERIALIZED
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VIEW conversion_funnel AS
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-- CTE какое кол-во человек записалось на курс
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WITH
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WITH
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enrolled_users AS (
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SELECT
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course_id,
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COUNT(*) AS enrolled
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FROM pet_enrollments pe
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GROUP BY course_id
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),
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enrolled_users
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AS
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(
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SELECT
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course_id,
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user_id,
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COUNT(*) OVER (PARTITION BY course_id) AS enrolled_count
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FROM pet_enrollments pe
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),
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-- СТЕ на начавших смотреть курс
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started_users AS (
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SELECT
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pc.id AS course_id,
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COUNT(DISTINCT plv.user_id) AS started
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FROM pet_courses pc
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LEFT JOIN pet_lessons pl
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ON pc.id = pl.course_id
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LEFT JOIN pet_lesson_views plv
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ON plv.lesson_id = pl.id
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GROUP BY pc.id
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),
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-- СТЕ на начавших смотреть курс
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started_users
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AS
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(
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SELECT
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eu.course_id,
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COUNT(DISTINCT plv.user_id) AS started
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FROM enrolled_users eu -- Базой берем записанных пользователей
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LEFT JOIN pet_lessons pl
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ON eu.course_id = pl.course_id
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LEFT JOIN pet_lesson_views plv
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ON plv.lesson_id = pl.id AND plv.user_id = eu.user_id
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-- Проверяем, что смотрел именно записанный юзер
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GROUP BY eu.course_id
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),
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--СТЕ на кол-во просмотров курса и прогресс по курсу
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user_progress AS (
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SELECT
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pc.id AS course_id,
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plv.user_id,
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COUNT(DISTINCT lesson_id) AS count_views,
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count_lesson_in_course.count_lesson_in_course AS count_lesson_in_course,
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COUNT(DISTINCT lesson_id) * 1.0 / count_lesson_in_course AS progress
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FROM pet_courses pc
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LEFT JOIN pet_lessons pl
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ON pl.course_id = pc.id
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LEFT JOIN pet_lesson_views plv
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ON plv.lesson_id = pl.id
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LEFT JOIN (
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SELECT
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pl.course_id,
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COUNT(*) AS count_lesson_in_course
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FROM pet_lessons pl
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GROUP BY pl.course_id
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--СТЕ на кол-во просмотров курса и прогресс по курсу
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user_progress
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AS
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(
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SELECT
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eu.course_id,
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eu.user_id,
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COUNT(DISTINCT plv.lesson_id) * 1.0 / count_lesson_in_course.count_lesson_in_course AS progress
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FROM enrolled_users eu -- Базой берем записанных пользователей
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LEFT JOIN pet_lessons pl
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ON pl.course_id = eu.course_id
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LEFT JOIN pet_lesson_views plv
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ON plv.lesson_id = pl.id AND plv.user_id = eu.user_id -- Просмотры могут быть NULL, если записался, но не смотрел
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LEFT JOIN (
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SELECT
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pl.course_id,
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COUNT(*) AS count_lesson_in_course
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FROM pet_lessons pl
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GROUP BY pl.course_id
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) AS count_lesson_in_course
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ON count_lesson_in_course.course_id = pc.id
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ON count_lesson_in_course.course_id = eu.course_id
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GROUP BY eu.course_id, eu.user_id, count_lesson_in_course.count_lesson_in_course
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),
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main_table
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AS
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(
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'registered' AS stage_name,
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0 AS stage_order,
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(SELECT COUNT(*)
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FROM pet_users pu) AS users_count,
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ROUND(100, 2) || '%' AS conversion_from_previous,
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ROUND(100, 2) || '%' AS conversion_from_start
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GROUP BY pc.id, plv.user_id, count_lesson_in_course
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),
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FROM pet_courses pc
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main_table AS (
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'registered' AS stage_name,
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0 AS stage_order,
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(SELECT COUNT(*) FROM pet_users pu) AS users_count,
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ROUND(100, 2) || '%' AS conversion_from_previous,
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ROUND(100, 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'enrolled' AS stage_name,
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1 AS stage_order,
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enrolled_users.enrolled,
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ROUND(enrolled_users.enrolled * 100.0 / (SELECT COUNT(*) FROM pet_users pu), 2) || '%' AS conversion_from_previous,
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ROUND(enrolled_users.enrolled * 100.0 / (SELECT COUNT(*) FROM pet_users pu), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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LEFT JOIN enrolled_users
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ON enrolled_users.course_id = pc.id
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'started' AS stage_name,
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2 AS stage_order,
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started_users.started,
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ROUND(started_users.started * 100.0 / enrolled_users.enrolled, 2) || '%' AS conversion_from_previous,
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ROUND(started_users.started * 100.0 / (SELECT COUNT(*) FROM pet_users pu), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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LEFT JOIN started_users
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ON started_users.course_id = pc.id
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LEFT JOIN enrolled_users
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ON enrolled_users.course_id = pc.id
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'mid_progress' AS stage_name,
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3 AS stage_order,
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( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 0.5
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),
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ROUND(( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 0.5) * 100.0 / started_users.started, 2) || '%' AS conversion_from_previous,
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ROUND(( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 0.5) * 100.0 / (SELECT COUNT(*) FROM pet_users pu), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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LEFT JOIN started_users
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ON started_users.course_id = pc.id
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'completed' AS stage_name,
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4 AS stage_order,
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( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 1),
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ROUND(( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 1) * 100.0 /
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( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 0.5), 2) || '%' AS conversion_from_previous,
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ROUND(( SELECT COUNT(*) FROM user_progress
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WHERE user_progress.course_id = pc.id AND user_progress.progress >= 1) * 100.0 /
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(SELECT COUNT(*) FROM pet_users pu), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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ORDER BY course_id, stage_order
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)
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'enrolled' AS stage_name,
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1 AS stage_order,
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COALESCE(eu.enrolled_count, 0),
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ROUND(COALESCE(eu.enrolled_count, 0) * 100.0 / NULLIF((SELECT COUNT(*) FROM pet_users), 0), 2) || '%' AS conversion_from_previous,
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ROUND(COALESCE(eu.enrolled_count, 0) * 100.0 / NULLIF((SELECT COUNT(*) FROM pet_users), 0), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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LEFT JOIN (SELECT course_id, MAX(enrolled_count) AS enrolled_count
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FROM enrolled_users
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GROUP BY course_id) eu
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ON eu.course_id = pc.id
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'started' AS stage_name,
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2 AS stage_order,
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COALESCE(su.started, 0),
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ROUND(COALESCE(su.started, 0) * 100.0 / NULLIF(eu.enrolled_count, 0), 2) || '%' AS conversion_from_previous,
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ROUND(COALESCE(su.started, 0) * 100.0 / NULLIF((SELECT COUNT(*) FROM pet_users), 0), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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LEFT JOIN (SELECT course_id, MAX(enrolled_count) AS enrolled_count
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FROM enrolled_users
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GROUP BY course_id) eu
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ON eu.course_id = pc.id
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LEFT JOIN started_users su
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ON su.course_id = pc.id
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'mid_progress' AS stage_name,
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3 AS stage_order,
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(SELECT COUNT(*)
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FROM user_progress up
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WHERE up.course_id = pc.id AND up.progress >= 0.5),
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ROUND((SELECT COUNT(*)
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FROM user_progress up
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WHERE up.course_id = pc.id AND up.progress >= 0.5) * 100.0 / NULLIF(su.started, 0), 2) || '%' AS conversion_from_previous,
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ROUND((SELECT COUNT(*)
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FROM user_progress up
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WHERE up.course_id = pc.id AND up.progress >= 0.5) * 100.0 / NULLIF((SELECT COUNT(*) FROM pet_users), 0), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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LEFT JOIN started_users su
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ON su.course_id = pc.id
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UNION ALL
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SELECT
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pc.id AS course_id,
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pc.title AS course_title,
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'completed' AS stage_name,
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4 AS stage_order,
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(SELECT COUNT(*)
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FROM user_progress up
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WHERE up.course_id = pc.id AND up.progress >= 1),
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ROUND((SELECT COUNT(*)
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FROM user_progress up
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WHERE up.course_id = pc.id AND up.progress >= 1) * 100.0 / NULLIF((SELECT COUNT(*) FROM user_progress up WHERE up.course_id = pc.id AND up.progress >= 0.5), 0), 2) || '%' AS conversion_from_previous,
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ROUND((SELECT COUNT(*)
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FROM user_progress up
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WHERE up.course_id = pc.id AND up.progress >= 1) * 100.0 / NULLIF((SELECT COUNT(*) FROM pet_users), 0), 2) || '%' AS conversion_from_start
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FROM pet_courses pc
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)
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-- main select
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SELECT
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SELECT
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course_id,
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course_title,
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stage_name,
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users_count,
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conversion_from_previous,
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conversion_from_start
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FROM main_table;
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FROM main_table
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ORDER BY course_id, stage_order;
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@@ -1,14 +1,24 @@
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-- 1. Задание 1: Анализ drop-off точек
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-- Используя conversion_funnel, найди курсы с самым большим процентом отвала между этапами enrolled → started (WHERE stage_name IN (...))
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WITH
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drop_off
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AS
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(
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SELECT
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course_id,
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stage_name,
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users_count,
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LAG(users_count) OVER (PARTITION BY course_id) AS prev
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FROM conversion_funnel
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)
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SELECT
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course_id,
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stage_name,
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conversion_from_previous,
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conversion_from_start
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FROM conversion_funnel
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WHERE stage_name IN ('started');
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ROUND(1 - users_count * 1.0 / NULLIF(prev, 0), 2) * 100 || '%' AS percent_of_drop
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FROM drop_off
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WHERE stage_name = 'started'
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ORDER BY percent_of_drop DESC
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-- ОТВЕТ: Самые большие проценты отвала между enrolled и started замечены на курсе 1 и 3 (62 и 67% соответственно).
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Reference in New Issue
Block a user