pavel
151 lines
3.0 KiB
SQL
151 lines
3.0 KiB
SQL
/* Задание 1 */
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SELECT
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u.id,
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u."name",
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o.id AS order_id,
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o.order_date,
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ROW_NUMBER() OVER (
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PARTITION BY u.id
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ORDER BY o.order_date) AS order_number_for_user
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FROM
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users u
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INNER JOIN
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orders o ON u.id = o.user_id
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/* Задание 2 */
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WITH order_revenue_cte AS (
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SELECT
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oi.order_id,
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oi.quantity * oi.price_at_purchase AS order_revenue
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FROM
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order_items oi
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)
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SELECT
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u.id,
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u."name",
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o.id AS order_id,
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o.order_date,
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orc.order_revenue,
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sum(orc.order_revenue) OVER (
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PARTITION BY u.id
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ORDER BY o.order_date
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ROWS UNBOUNDED PRECEDING
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) AS running_revenue_for_user
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FROM
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users u
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INNER JOIN
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orders o ON u.id = o.user_id
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INNER JOIN
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order_revenue_cte orc ON o.id = orc.order_id
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/* Задание 3 */
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WITH user_revenue_cte AS (
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SELECT
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o.user_id,
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oi.quantity * oi.price_at_purchase AS order_revenue,
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sum(oi.quantity * oi.price_at_purchase) OVER (
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PARTITION BY o.user_id) AS user_total_revenue
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FROM
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orders o
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INNER JOIN
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order_items oi ON o.id = oi.order_id)
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SELECT DISTINCT
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u."name",
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urc.user_total_revenue,
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RANK() OVER (ORDER BY urc.user_total_revenue DESC) AS revenue_rank,
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DENSE_RANK() OVER (ORDER BY urc.user_total_revenue DESC) AS revenue_dense_rank
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FROM
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users u
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INNER JOIN
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user_revenue_cte urc ON u.id = urc.user_id
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/* Задание 4 */
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SELECT
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u.name AS user_name,
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o.id AS order_id,
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o.order_date,
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FIRST_VALUE(o.order_date) OVER (
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PARTITION BY o.user_id
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ORDER BY o.order_date
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) AS first_order_date,
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LAST_VALUE(o.order_date) OVER (
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PARTITION BY o.user_id
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ORDER BY o.order_date
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ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING
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) AS last_order_date
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FROM
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users u
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INNER JOIN
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orders o ON u.id = o.user_id;
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/* Задание 5 */
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SELECT
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u.name,
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o.id,
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count(o.id) OVER (
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PARTITION BY o.user_id) AS orders_per_user
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FROM
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users u
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INNER JOIN
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orders o ON u.id = o.user_id
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/* Задание 6 */
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WITH order_revenue_cte AS (
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SELECT
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oi.order_id,
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oi.quantity * oi.price_at_purchase AS order_revenue
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FROM
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order_items oi
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)
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SELECT
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u.name,
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o.id,
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o.order_date,
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orc.order_revenue,
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lag(orc.order_revenue) OVER (
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PARTITION BY o.user_id
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ORDER BY o.order_date
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) AS prev_order_revenue
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FROM
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users u
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INNER JOIN
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orders o ON u.id = o.user_id
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INNER JOIN
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order_revenue_cte orc ON o.id = orc.order_id
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/* Задание 7 */
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WITH category_revenue_cte AS (
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SELECT
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p.category,
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date_trunc('day', o.order_date)::date AS order_period,
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sum(oi.quantity * oi.price_at_purchase) AS daily_category_revenue
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FROM
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products p
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LEFT JOIN
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order_items oi ON p.id = oi.product_id
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INNER JOIN
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orders o ON oi.order_id = o.id
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GROUP BY 1, 2)
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SELECT
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cr_cte.*,
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sum(cr_cte.daily_category_revenue) OVER (
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PARTITION BY cr_cte.category
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ORDER BY cr_cte.order_period
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ROWS UNBOUNDED PRECEDING
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) AS running_category_revenue
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FROM
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category_revenue_cte cr_cte;
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