homework, pet project DE Dmitry_Medvedev #1
@@ -19,12 +19,13 @@ INNER JOIN
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WITH order_revenue_cte AS (
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SELECT
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oi.order_id,
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oi.quantity * oi.price_at_purchase AS order_revenue
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sum(oi.quantity * oi.price_at_purchase) AS order_revenue -- добавил агреграт по всем поз. в заказе
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FROM
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order_items oi
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GROUP BY oi.order_id
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)
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SELECT
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u.id,
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u.id AS user_id ,
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u."name",
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o.id AS order_id,
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o.order_date,
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@@ -32,7 +33,6 @@ SELECT
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sum(orc.order_revenue) OVER (
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PARTITION BY u.id
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ORDER BY o.order_date
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ROWS UNBOUNDED PRECEDING
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) AS running_revenue_for_user
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FROM
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users u
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@@ -40,6 +40,8 @@ INNER JOIN
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orders o ON u.id = o.user_id
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INNER JOIN
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order_revenue_cte orc ON o.id = orc.order_id
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WHERE o.status NOT IN ('cancelled', 'refunded') -- добавил условие не включать отмененные заказы
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/* Задание 3 */
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@@ -47,14 +49,13 @@ INNER JOIN
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WITH user_revenue_cte AS (
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SELECT
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o.user_id,
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oi.quantity * oi.price_at_purchase AS order_revenue,
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sum(oi.quantity * oi.price_at_purchase) OVER (
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PARTITION BY o.user_id) AS user_total_revenue
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sum(oi.quantity * oi.price_at_purchase) AS user_total_revenue
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FROM
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orders o
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INNER JOIN
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order_items oi ON o.id = oi.order_id)
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SELECT DISTINCT
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order_items oi ON o.id = oi.order_id
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GROUP BY o.user_id) -- добавил group by, костыль убран
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SELECT
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u."name",
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urc.user_total_revenue,
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RANK() OVER (ORDER BY urc.user_total_revenue DESC) AS revenue_rank,
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@@ -62,7 +63,7 @@ SELECT DISTINCT
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FROM
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users u
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INNER JOIN
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user_revenue_cte urc ON u.id = urc.user_id
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user_revenue_cte urc ON u.id = urc.user_id;
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/* Задание 4 */
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@@ -104,10 +105,10 @@ INNER JOIN
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WITH order_revenue_cte AS (
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SELECT
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oi.order_id,
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oi.quantity * oi.price_at_purchase AS order_revenue
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sum(oi.quantity * oi.price_at_purchase) AS order_revenue
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FROM
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order_items oi
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)
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GROUP BY oi.order_id) -- добавил group by по order_id, теперь это сумма всего заказа, а не строки
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SELECT
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u.name,
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o.id,
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@@ -122,7 +123,7 @@ FROM
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INNER JOIN
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orders o ON u.id = o.user_id
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INNER JOIN
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order_revenue_cte orc ON o.id = orc.order_id
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order_revenue_cte orc ON o.id = orc.order_id;
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/* Задание 7 */
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